0=9x^2-2x-44

Solution for 0=9x^2-2x-44 equation:

0=9x^2-2x-44

We move all terms to the left:

0-(9x^2-2x-44)=0

We add all the numbers together, and all the variables

-(9x^2-2x-44)=0

We get rid of parentheses

-9x^2+2x+44=0

a = -9; b = 2; c = +44;
Δ = b2-4ac
Δ = 22-4·(-9)·44
Δ = 1588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1588}=\sqrt{4*397}=\sqrt{4}*\sqrt{397}=2\sqrt{397}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{397}}{2*-9}=\frac{-2-2\sqrt{397}}{-18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{397}}{2*-9}=\frac{-2+2\sqrt{397}}{-18}
$